Slide
5
Substituting
the stress from previous expressions, we find that torque is the
integral of G phi over L times rho squared dA. Pulling out the terms
that do not vary over the cross section we get that the torque is
G phi over L, times the polar moment of inertia, which is the integral
of rho squared over the cross section. We will discuss polar moment
of inertia, J, on the next slide. Rearranging the terms, we can
write the angle of twist phi as T L over G J. We can also find the
stress from tau=G rho phi over L, and then substituting for phi
to get tau=T rho over J.
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